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Simplify first :
1) R5 and R6 are in series, so what would the equivalent R in place of them be ?
2) The equivalent R from 2) is in parallel with R4, so whats that new equivalent ?
3) You now have a simple V divider to compute V4......
Regards, Dana.
1) R5 and R6 are in series, so what would the equivalent R in place of them be ?
2) The equivalent R from 2) is in parallel with R4, so whats that new equivalent ?
3) You now have a simple V divider to compute V4......
Regards, Dana.
Once you're done 1 and 2, redraw the schematic in a more conventional manner. Start with the current source to the left, with any resistors directly in parallel with it. Extend the + and - (GND) rails to the right, and then fill in the remaining resistors and equivalent resistors. The + terminal connects to three resistors in the original schematic, so there should be three branches in parallel between the + and - rails.
Once you do that, you can collapse the entire network to a single equivalent resistor across the current source. This gives the current source a terminal voltage. With this voltage and Ohm's Law, you can work out the current through, and voltage across, each resistor.
ak
Once you do that, you can collapse the entire network to a single equivalent resistor across the current source. This gives the current source a terminal voltage. With this voltage and Ohm's Law, you can work out the current through, and voltage across, each resistor.
ak
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