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Power Calculation

electronicsLearner77

Jul 2, 2015
306
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Jul 2, 2015
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Consider a simple switched circuit VDD = 600V RL = 100 Ohm. The on-state resistance of the switch, Ron = 2Ohms.
What is the magnitude of the power in kW, provided by the source when the switch is closed?

1693054834418.png

Power = V^2/R = 600 * 600 / 102 =3.52kW. The calculations are ok?
 

danadak

Feb 19, 2021
797
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Feb 19, 2021
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797
P = E**2 / R =
R = (100 + 2), V = 600.

I = V / R = 600 / 102

Pswitch = I**2 x R = (600 / 102 )**2 x 2 ohms =

1693091889548.png


Regards, Dana.
 
Last edited:

Kiwi

Jan 28, 2013
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Jan 28, 2013
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476
Calculation looks correct, but 3.53kW would be a more accurate answer.
3.5294kW
 
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