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Gaussmeter dc bias

gjoo

May 22, 2013
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Can someone explain the equation for vr2 in this diagram. An op amp with an 100 ohm output receiver which is fed from an hall sensor I'm not sure how to calculate the adjustable 10k resistor with 5v input into this circuit. I know it is a dc bias. Any help appreciated.
 

gjoo

May 22, 2013
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I meant to write that the dc bias is biasing the output from the op amp, but how do we calculate how much it is biasing
 

gjoo

May 22, 2013
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I've posted the circuit below
 
Last edited:

gjoo

May 22, 2013
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Here is a picture of the circuit
 

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gjoo

May 22, 2013
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I think this pic is clearer
 

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davenn

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Sep 5, 2009
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Hi
sorry I cant help, just wanted to say hi and hope some one else can help you out :)
 

kellys_eye

Jun 25, 2010
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What's to calculate? It's a pot (presumably linear law) across a 5V supply therefore the voltage at the wiper will be directly proportional to its position. Assuming a 10 turn pot (common) you get 0.5V per revolution all the way from 0 to 5V.

Or am I missing something?
 

gjoo

May 22, 2013
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How does the output of the pot combine with the output of the op amp? Would we treat us at a voltage divider 5v(0 to 10000)(100)/100+(0to10,000)
 

kellys_eye

Jun 25, 2010
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In this case the op-amp output would only have an effect if/when it exceeded the DC level set by the pot - thus a bias.
 

gjoo

May 22, 2013
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So, when the op amp exceeds the dc bias, all we do is subtract the bias from the op amp output?
 

kellys_eye

Jun 25, 2010
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Not here - this isn't a summation circuit. Once the op-amp output exceeds the voltage at the wiper of the pot the op-amp voltage becomes the 'dominant' signal. It's more like a 'squelch' setting in that the pot level sets the point at which the op-amp output has to exceed in order for a change to be effected.
 

gjoo

May 22, 2013
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Not here - this isn't a summation circuit. Once the op-amp output exceeds the voltage at the wiper of the pot the op-amp voltage becomes the 'dominant' signal. It's more like a 'squelch' setting in that the pot level sets the point at which the op-amp output has to exceed in order for a change to be effected.
Thanks for all the help. I understand it now.
 

gjoo

May 22, 2013
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Just one last question, how does the 100 ohm resistor affect that bias?
 

gjoo

May 22, 2013
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How would the resistive load equation look for this circuit?
 
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