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# Help with Nortons Equivalent. 2 sources... confused lots.

#### Ledwardz

Dec 21, 2010
43
Hi, ive attached the circuit i have. My first problem was;

do i work out the norton resistances from A-B in which case the Norton resistance is in parallel and equal to (15/8)k

or are the resistances from the 10v which gives a total resistance of 8K

meh..... its pointless me trying to explain hopefully the attachment will make it a little more clear im confused on a few things. any help appreciated.

(also, sorry for the 'crapness' of the photo, my scanner is broken)
its a 10v supply to the left and 1ma supply to the right with a 3k resistor to the top left and 5k between the 2 supplies.

Thanks for looking.

#### (*steve*)

##### ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd
Moderator
Jan 21, 2010
25,510
I think you may have to try attaching that diagram a second time...

#### Ledwardz

Dec 21, 2010
43
erm it should b there now dnt know y tht didn't work the first time.

#### Attachments

• IMG_20101221_185735.jpg
10.9 KB · Views: 148

#### Ledwardz

Dec 21, 2010
43
actually this is probably more clear..... should have posted this first.

#### Attachments

• Screenshot.jpg
69.7 KB · Views: 177

#### barathbushan

Sep 26, 2009
223
you have to convert the voltage source in series with the 3k resistors , then the circuit turns out to be two current sources and two resistors in parallel , you add up the current sources and compute the parallel resistor combination as shown in the diagram

I think this thread must have been started in the homework section

#### Attachments

• Uwntitled.jpg
29.2 KB · Views: 312
Last edited:

#### Ledwardz

Dec 21, 2010
43
you have to convert the voltage source in series with the 3k resistors , then the circuit turns out to be two current sources and two resistors in parallel , you add up the current sources and compute the parallel resistor combination as shown below

I think this thread must have been started in the homework section

Thats brilliant. Thanks. could you tell me why you didn't include the 5k resistor when working out the current for the 10v supply to get the current for it?

#### barathbushan

Sep 26, 2009
223
That's because the 5k wasn't in series with the voltage source , which means it doesn't come into the picture when the 10v voltage source was converted to 3.3ma current source

here's a golden rule in solving network problems

Voltage with a series resistor , and a current source with a shunt resistor are interconvertible

#### Ledwardz

Dec 21, 2010
43
That's because the 5k wasn't in series with the voltage source , which means it doesn't come into the picture when the 10v voltage source was converted to 3.3ma current source

here's a golden rule in solving network problems

Voltage with a series resistor , and a current source with a shunt resistor are interconvertible

cheers!

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