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Wingnut,
About R3,
It is in the correct location as it's purpose is to limit the initial current drown from the battery
at the first moment.
Assume the Cap is fully discharge,
at the first moment you close the switch the battery feels a short on it's terminals(limited only by a very low internal resistance of the cap-practically a short).
That is not a good thing for the battery and it's life time...
Yes,It will slower the charging time , but nothing you could notice:
Assuming C=1000uF and R=47 ohm, we get a time constant of T=0.047 seconds
the cap will be 99% charged in about 5*T=0.25Sec,
which is less than the time a person presses the push-button...
What current for the led. Or a link to data
I have 74LS05 and CD4069UBE and GDF543. I am hoping the first will be suitable.Non of them will do:
The 4000 series because of poor output drive.
The op. amps and comparators because of to high "STBY current"
Have you got any MOSFETs?
"I assume that R1 leaks away current/voltage till it drops to a level below what the chip recognises as an "on" voltage, at which point, the output changes post-haste"
Yes basically,
put a bit differently:
C is discharge through R1 till the input voltage is below VinL of the inverter ,
causing the output to switch from VoL to VoH .
Dont know what GDF543 is.
The 74LS series draw too much STBY power .
I would test the circuit with the CD4069UBE:
1.with "parallel" INs and OUTs.
2.use a 5ma LED or less( if you have a 2ma one even better).
You will not get the proper illumination you need,
but just test the circuits operation.
order the 74HC14,when you have it ,use it in the real thing...
Collin is not being rude, just being himself. Have a look at some of his other posts.care to explain or just be rude?
wingnut,
Glad to hear that.
what values have you used ?
You can shorten the "press time" by using a lower R3(say 22 ohm)
It is a "game of balance" with battery life.
I am using the 3 left inputs in // with the 3 left outputs only.Something is still wrong ,the STBY current of 1.3ma is way too high!
You should get no more than a few uA(a factor of 1000 down!).
I guess you didn't tie the unused inputs to GND or VCC...
I'd go with the HEF40106 and wire all six inverters in parallel in dorke's circuit.
Something is still wrong ,the STBY current of 1.3ma is way too high!
You should get no more than a few uA(a factor of 1000 down!).
I guess you didn't tie the unused inputs to GND or VCC...