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can such water flow support 100 families ( 220V) 15000W -20000W ?


Wim Ton

Jan 1, 1970
Difficult to say from a picture

Depends on drop and the amount of water

The energy from the stream is n.m.g.h = 150000 watt

m = mass of water per second in kg/s
g = gravity (9.8 m/s^2)
h = the drop in m
n = efficiency (turbine, generator, presure drop in the pipe or channel

So with a drop of 2 m (more or less the minimum for a turbine or a
waterwheel) and 75% effieciency you need about 1 m^3 /sec

See also

Google is your friend

What is the point of posting this on alt.microcontroller.8bit ???



Jan 1, 1970
Hamish said:
You need to put more information up

1 what is the flow rate in liters per second
2 what is the fall ( Height from top of dam to generator )

Power available is = flowrate ( liters per second ) times fall (
meters )time 9.8 ( gravatitional constant ) * 0.8 ( effenciy of
turbine and generator )

for example

flow 100 l/s
head 10 m

Power available = 100 * 10 * 9.8 * 0.8
= 7840 w
= 7.84 Kw

If you are not sure of how to get the flowrate and fall, ask me here
for more details

Also, the flow rate is assuming you funnel all the water through the
turbine. ie: if you have a flow rate of 1 meter/sec total through the
flume but some of the water bypasses the turbine you need to account for
that loss.
The stream shown in your picture wont support 100 families, 1 maybe with
lots of batteries for load, but not 100. I'm estimating a fall of about a
half meter and maybe 100 to 200 l/s (I'm just guessing) Its hard to tell
too much from the pictures about either fall or flow rate.
Measure it like another poster said, then you'll have some hard data