Since a thin round copper wire has a very low emissivity it wont
give up its heat all that fast.
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Ever hear of convection, dumbass?
Got some numbers? Or is this going to be another one of your
unsubstantiated claims?
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This will mean that your thermal
gradient won't be as prevalent as you suggest. The proof is when one
takes a copper wire and places it across a battery's terminals.
Notice how the entire wire turns a nice cherry red quite evenly, all
the way up to where it is attached to any form of sinking element.
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I see. Just by _looking_ at the glowing wire you can tell what the
temperature differential is between the center of the wire and its
surface? Amazing!!!
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The current throughout the wire will be even,
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No, it won't. it'll be lower in the parts of the wire which are
hotter.
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and it is that current
which generates the heat, or more precisely, the resistance to said
current flow.
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The current changes the temperature of the wire, but it doesn't
generate the resistance of the wire. The wire's resistance and its
temperature coefficient of resistance are due to the resistivity and
tempco of the material the wire is made of.
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If the wire were giving up its heat real fast, like that of a finned
heat sink with air passing over it, I might agree.
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Whether you agree or not is immaterial. The phenomenon occurs with
or without your permission.
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In the case of
bare copper, however, the temperature throughout the wire is going to
be very even. Your gradient will be nearly undetectable.
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Point is, dimwit, it'll still be there.
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For a very large diameter copper bus, it MIGHT have a slight
gradient between the center and the outer surface, but not much. For
wire, it is as even as even gets.
Got some numbers, or is that just some more of your bullshit
opinion?
