Hi All,
I was wondering if someone can help me understand the attached circuit.
this is what i have measured:-
Input to the opamp is -0.5V (from a PSU), because of feedback the inverting terminal must be at the same potential ie -0.5V because of virtual earth of opamp.
The gate of the FET is at 0.34V, source is at -0.5V (held there by pin 2 of the opamp), drain is at 0V, VGS = 0.82v and VDS = -0.5V.
Is my analogy correct, the n channel is working because the drain is more positive than the source i.e. 0V > -0.5V
Also the gate is more positive than the source i.e. 0.34V > -0.5V.
the VGS(th) of the FET is 0.6V, so am i correct in saying that i have a potential divider arrangement with the 0.84V at VGS, drain at -0.5V whch leaves 0.34V at the gate?
The output is then simply -0.5V/1M = 0.5uA (negative current)
I get the following witha -1.5V at pin 3, pin 2 is also at -1.5V, gate is 0.66V, source is at -1.5V, VGS = 0.84, VDS = 1.5V. So again am i right in saying 1.5-0.84 = 0.66 the gate voltage.
Is the FET in triode mode operation?
I would really appreciate any help.
Best regards,
Raj
I was wondering if someone can help me understand the attached circuit.
this is what i have measured:-
Input to the opamp is -0.5V (from a PSU), because of feedback the inverting terminal must be at the same potential ie -0.5V because of virtual earth of opamp.
The gate of the FET is at 0.34V, source is at -0.5V (held there by pin 2 of the opamp), drain is at 0V, VGS = 0.82v and VDS = -0.5V.
Is my analogy correct, the n channel is working because the drain is more positive than the source i.e. 0V > -0.5V
Also the gate is more positive than the source i.e. 0.34V > -0.5V.
the VGS(th) of the FET is 0.6V, so am i correct in saying that i have a potential divider arrangement with the 0.84V at VGS, drain at -0.5V whch leaves 0.34V at the gate?
The output is then simply -0.5V/1M = 0.5uA (negative current)
I get the following witha -1.5V at pin 3, pin 2 is also at -1.5V, gate is 0.66V, source is at -1.5V, VGS = 0.84, VDS = 1.5V. So again am i right in saying 1.5-0.84 = 0.66 the gate voltage.
Is the FET in triode mode operation?
I would really appreciate any help.
Best regards,
Raj